Analyzing a new reaction
Consider the following elementary steps that make up the mechanism of a certain reaction:
3A→B+C
B+2D→C+F
1. What is the overall reaction?
2. What is the rate law for step one of this reaction?
3. What is the rate law for step two of this reaction?
1: Given that the reaction completes via the following two elementary steps.
3A----> B+C ----- (1)
B+2D -----> C+F ---- (2)
Now we can get the overall reaction by adding the abve two reactions. Hence the overall reaction is
3A + B + 2D ----- > B + C + C + F
Now 'B' will cancel out from both the sides. Hene the overall reaction is
3A + 2D ----- > 2C + F (answer)
(2): Rate law is proportional to the concentration of all the reactants raised to a power equals to the coffecient
Step-1 of the reaction is
3A ----> B+C
Hence rate law is
rate = k x [A]3 (answer)
(3): Step-2 of the reaction is
B + 2D ----> C + F
Hence rate law is
rate = k x [B]x[D]2 ( answer)
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