A reaction mechanism is defined as the sequence of reaction steps that define the pathway from reactants to products. Each step in a mechanism is an elementary reaction, which describes a single molecular event of usually one or two molecules interacting.
The rate law for an overall reaction is the rate law for the slowest step in the mechanism, which is directly related to the stoichiometric coefficients of the reactants.
The exception to this rule occurs when the slowest step contains intermediates. In these cases, the slowest step is usually preceded by an equilibrium step, which can be used to substitute for the intermediates in the overall rate law.
What is the rate law for the following mechanism in terms of the overall rate constant k?
Step1:Step2:A+BB+C⇌→CD(fast)(slow) |
Express your answer in terms of k and the necessary concentrations (e.g., k*[A]^3*[D]).
Part B
Consider the reaction
2X2Y2+Z2⇌2X2Y2Z
which has a rate law of
rate= k[X2Y2][Z2]
Select a possible mechanism for the reaction.
Consider the reaction
which has a rate law of
Select a possible mechanism for the reaction.
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(1) The reactions given are
As it is explained that rate of reaction is governed by the slower
step thus the rate of reaction
As the [C] is not the reactant but an intermedaite product,
therefore for complete reaction the rate law need to be given in
terms of [A] and [B]
From the first step equillibrium constant
Substituting [C] in the slow step rate equation
where kk'= K
(2)
According to rate law
Rate = K[Reactant]
The rate law given for the reaction =
For that need to be in reactants of slow step.
So the reaction steps can be either option B or option C
The reaction steps given in option B are
Reaction steps given in option C are
Steps given in Option B are the reaction steps as .
In option C the fast step is a dissociation step that need to be considered in rate equation.
Therefore answer is B
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