Question

For the reaction: Dihydroxyacetone phosphate to glyceraldehyde 3-phosphate, delta G is 1.8 kcal/mol. What ratio of...

For the reaction: Dihydroxyacetone phosphate to glyceraldehyde 3-phosphate, delta G is 1.8 kcal/mol. What ratio of product/reactant must be maintained in order to keep the reaction going in a forward direction?

Homework Answers

Answer #1

^G' < 0
^G' + 2.303 RT Log (glyceraldehyde 3-phosphate) / (dihydroxyacetone phoshate) < 0
1.8 kcal = 1800 cal

1800 cal/mol + (2.303) (1.987cal/mol K) (298K) log (glyceraldehyde 3-phosphate) / (dihydroxyacetone phoshate) < 0

1364 Log (glyceraldehyde 3-phosphate) / (dihydroxyacetone phoshate) < -1800cal/mol

Log (glyceraldehyde 3-phosphate) / (dihydroxyacetone phoshate) < -1800 / 1364

Log (glyceraldehyde 3-phosphate) / (dihydroxyacetone phoshate) < -1.32cal/mol

(glyceraldehyde 3-phosphate) / (dihydroxyacetone phoshate) < 0.048 cal/mol

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