Question

Consider the following reaction where Kc = 6.50×10-3 at 298 K. 2NOBr(g) 2NO(g) + Br2(g) A...

Consider the following reaction where Kc = 6.50×10-3 at 298 K. 2NOBr(g) 2NO(g) + Br2(g) A reaction mixture was found to contain 0.101 moles of NOBr(g), 5.03×10-2 moles of NO(g), and 4.51×10-2 moles of Br2(g), in a 1.00 liter container. Is the reaction at equilibrium? If not, what direction must it run in order to reach equilibrium? The reaction quotient, Qc, equals . The reaction A. must run in the forward direction to reach equilibrium. B. must run in the reverse direction to reach equilibrium. C. is at equilibrium.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Consider the following reaction where Kc = 6.50×10-3 at 298 K: 2 NOBr (g) 2 NO...
Consider the following reaction where Kc = 6.50×10-3 at 298 K: 2 NOBr (g) 2 NO (g) + Br2 (g) A reaction mixture was found to contain 8.07×10-2 moles of NOBr (g), 4.06×10-2 moles of NO (g), and 4.46×10-2 moles of Br2 (g), in a 1.00 liter container. Indicate True (T) or False (F) for each of the following: 1. In order to reach equilibrium NOBr(g) must be consumed . 2. In order to reach equilibrium Kc must decrease ....
A) Consider the following reaction where Kc = 0.159 at 723 K. N2(g) + 3H2(g) 2NH3(g)...
A) Consider the following reaction where Kc = 0.159 at 723 K. N2(g) + 3H2(g) 2NH3(g) A reaction mixture was found to contain 4.94×10-2 moles of N2(g), 4.07×10-2 moles of H2(g) and 6.19×10-4 moles of NH3(g), in a 1.00 liter container. The reaction quotient, Qc, equals __________. The reaction__________________ A. must run in the forward direction to reach equilibrium. B. must run in the reverse direction to reach equilibrium. C. is at equilibrium. B) Consider the following reaction where Kc...
1) Consider the following reaction where Kc = 7.00×10-5 at 673 K. NH4I(s) --> NH3(g) +...
1) Consider the following reaction where Kc = 7.00×10-5 at 673 K. NH4I(s) --> NH3(g) + HI(g) A reaction mixture was found to contain 5.62×10-2 moles of NH4I(s), 1.12×10-2 moles of NH3(g), and 8.37×10-3 moles of HI(g), in a 1.00 liter container. Is the reaction at equilibrium? If not, what direction must it run in order to reach equilibrium? The reaction quotient, Qc, equals (???????) The reaction ????? A. must run in the forward direction to reach equilibrium. B. must...
Le Chantelier: Concentration Consider the following system at equilibrium where H=-16.1 kJ, and Kc=154, at 298...
Le Chantelier: Concentration Consider the following system at equilibrium where H=-16.1 kJ, and Kc=154, at 298 K. 2NO(g) + Br2(g) 2NOBr(g) When 0.36 moles of Br2(g) are added to the equilibrium system at constant temperature: the value of Kc A.increases                          B. decreases                           C. remains the same. the value of Qc A. is greater than Kc                            B. is equal to Kc                             C. is less than Kc the reaction must: A. run in the forward directin to restablish...
Consider the following reaction (assume an ideal gas mixture): 2NOBr(g) <--> 2NO(g) + Br2(g) A 1.0-liter...
Consider the following reaction (assume an ideal gas mixture): 2NOBr(g) <--> 2NO(g) + Br2(g) A 1.0-liter vessel was initially filled with pure NOBr, at a pressure of 0.685 atm, at 300 K. After equilibrium was established, the partial pressure of NOBr was 0.279 atm. What is Kp for the reaction? Report answer to 4 decimal points.
Consider the following reaction (assume an ideal gas mixture): 2NOBr(g) <--> 2NO(g) + Br2(g) A 1.0-liter...
Consider the following reaction (assume an ideal gas mixture): 2NOBr(g) <--> 2NO(g) + Br2(g) A 1.0-liter vessel was initially filled with pure NOBr, at a pressure of 0.893 atm, at 300 K. After equilibrium was established, the partial pressure of NOBr was 0.242 atm. What is Kp for the reaction? Report answer to 4 decimal points.
Nitrosyl bromide, NOBr, is formed in the reaction of nitric oxide, NO, with bromine, Br2: 2NO(g)+Br2(g)⇌2NOBr(g)...
Nitrosyl bromide, NOBr, is formed in the reaction of nitric oxide, NO, with bromine, Br2: 2NO(g)+Br2(g)⇌2NOBr(g) The reaction rapidly establishes equilibrium when the reactants are mixed. At this temperature the rate constant for the reverse reaction is 320. M−2s−1 . What is kf for the reaction?
Kc = 3.07 x 10-4 at 24°C for 2NOBr(g) ↔ 2NO(g) + Br2(g). If the initial...
Kc = 3.07 x 10-4 at 24°C for 2NOBr(g) ↔ 2NO(g) + Br2(g). If the initial concentration of NOBr = 0.802 M, what is the equilibrium concentration (in M to 4 decimal places) of NO?   
Nitrosyl bromide, NOBr, is formed in the reaction of nitric oxide, NO, with bromine, Br2: 2NO(g)+Br2(g)⇌2NOBr(g)...
Nitrosyl bromide, NOBr, is formed in the reaction of nitric oxide, NO, with bromine, Br2: 2NO(g)+Br2(g)⇌2NOBr(g) The reaction rapidly establishes equilibrium when the reactants are mixed. Part A At a certain temperature the initial concentration of NO was 0.400 M and that of Br2 was 0.255 M . At equilibrium the concentration of NOBr was found to be 0.250 M. What is the value of Kc at this temperature? Kc = 21.4 PART B At this temperature the rate constant...
One Question , Use this section to ask your question: 1. A student ran the following...
One Question , Use this section to ask your question: 1. A student ran the following reaction in the laboratory at 242 K: 2NOBr(g) 2NO(g) + Br2(g) When she introduced 0.146 moles of NOBr(g) into a 1.00 liter container, she found the equilibrium concentration of Br2(g) to be 1.77×10-2 M. Kc = B. at 237 K: When she introduced 0.125 moles of NOBr(g) into a 1.00 liter container, she found the equilibrium concentration of NOBr(g) to be 9.44×10-2 M. Calculate...