Question

Find H for the reaction 2 ZnS(s) + 3 O2(g) ---> 2 ZnO(s) + 2SO2​(g)

delta H f (ZnS,s) = -206.0 Kj/mol

delta H f (ZnO,s) -348.3 Kj/mol

delta Hf ( SO2, g) = -296.8 kj/mol

Answer 1

the reaction is

2ZnS(s) + 3 O2 (g) -------------------------> 2 ZnO (s) + 2 SO2 (g)

delta H f (O2) = 0 (because it is present in elemental state)

so , now according to reaction we are putting the values

[2 * (-206.0) + 0 ]-[ 2* (-348.3) + 2* (-296.8)]

[-412]-[-1290.2]

878.2 kj/mol

few of times u will get this answer negative which means this amount of heat is released after the reaction .

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