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How many amperes are required to deposit 0.103 grams of manganese metal in 273 seconds, from...

How many amperes are required to deposit 0.103 grams of manganese metal in 273 seconds, from a solution that contains Mn2+ ions?

Answer in amperes (A)

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Answer #1

Since from balanced equation it can be seen that to deposit 1 molecule of Mn we are required to transfer 2 electron to to deposit 1 mole i.e. equal to the molar mass of Mn ,we are required to transfer 2 mole of electrons i.e. 2 faraday charge . That's why I have used that relation .

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