Question

1. How many GRAMS of manganese(II) are present in 1.53 grams of manganese(II) sulfate ?  
grams manganese(II).


2. How many GRAMS of manganese(II) sulfate can be made from 2.46 grams of manganese(II) ?  
grams manganese(II) sulfate.

Answer 1

Mn has atomic mass of 54.94 g/mol while MnSO4 has molar mass of 151 g/mol

1) Moles of MnSO4 = ( mass / Molar mass of MnSO4) = ( 1.53g /151g/mol) = 0.0101 mol

Mn2+ moles produced by MnSO4 = 0.0101 ( since 1MnSO4 gives 1 Mn2+ )

Mn2+ mass = moles x atomic mass of Mn = 0.0101 molx 54.94g/mol = 0.547 g

2) Mn2+ moles = ( mass / atomic mass of Mn2+) = ( 2.46g /54.94g/mol) = 0.0448

MnSO4 moles produced = 0.0448

MnSO4 mass = moles x molar mass of MnSO4 = 0.0448 mol x 151 g/mol = 6.76 g