How many minutes will it take to electroplate 0.334 grams of copper metal, Cu(s), from a solution containing Cu2+(aq) with a current of 3.17 amps?
1 A = 1 C/s
F = 96,500 C/mole electron
ANSWER:
Given,
current, I = 3.17 A
weight of copper metal = 0.334 g
atomic mass of copper metal = 63.5 g/mol
number of moles of copper metal = (0.334 g)/(63.5 g/mol) = 0.00526 mol
1 mole of copper releases = 2 mole electrons
0.00526 moles of copper releases = 0.01052 moles electrons
Faradays constant, F =96500 C/mole electron
From electrochemistry:
Q = I x t = nF
where,
Q = charge
I = current
t = time
n = moles of electrons
F = faradays constant
Q = 3.17 C/s x t = 0.01052 mole electron x 96500 C/mole electron
time, t = 320.24 s = 5.34 min
Hence, 5.34 minutes will take to electroplate 0.334 grams of copper metal, Cu(s), from a solution containing Cu2+(aq) with a current of 3.17 A.
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