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Solve the initial value problem and determine the interval in which the solution is valid. Round...

Solve the initial value problem and determine the interval in which the solution is valid. Round your answer to three decimal places.

y′=6x^2/(6y^2−11), y(1)=0

2y^3=2x^3+11y-2

The solution is valid for (fill in the blank)<x<(fill in the blank)

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