So I am given a line of Yhat = .93x + 20.84. r = .62 and standard deviation of Y = 6.
Solve for standard deviation of X.
Given Regression Line:
Correlation coefficient r = 0.62
Standard Deviation of Y = = 6
To find Standard Deviation of X =
Slope of Regression Line is given by:
Here:
a = 0.93
r = 0.62
= 6
= To be found
Substituting, we get:
So,
So,
Answer is:
4
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