Question

In the following exercises, assuming that the thermometer readings are normally distributed, with a mean of...

In the following exercises, assuming that the thermometer readings are normally distributed, with a mean of 0 celsius and a standard deviation of 1.00 celsius. A thermometer is randomly selected and tested. In each case, calculate the probability of each reading.

to. greater than 1.25
b. greater than -1.75
c. less than 2.50
d. less than -3.75
and. between -2.45 and -2.00
F. between -1.00 and 4.00
g. P (-1.96 <z <1.96)

Homework Answers

Answer #1

Solution :

Given that,  

Using standard normal table ,

a.

P(z > 1.25) = 1 - P(z < 1.25) = 1 - 0.8944 = 0.1056

b.

P(z > -1.75) = 1 - P(z < -1.75) = 1 - 0.0401 = 0.9599

c.

P(z < 2.50) = 0.9938

d.

P(z < -3.75) = 0.0001

and

P(-2.45 < z < -2.00)

= P(z < -2.00) - P(z < -2.45)

= 0.0228 - 0.0071

= 0.0217

P(-2.45 < z < -2.00) = 0.0217

f

P(-1.00 < z < 4.00)

= P(z < 4.00) - P(z < -1.00)

= 1 - 0.1587

= 0.8413

P(-1.00 < z < 4.00) = 0.8413

g

P(-1.96 < z < 1.96)

= P(z < 1.96) - P(z < -1.96)

= 0.975 - 0.025

= 0.95

P(-1.96 < z < 1.96) = 0.95

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Standard Normal Distribution – In Exercises 9 – 13, assume that thermometer readings are normally distributed...
Standard Normal Distribution – In Exercises 9 – 13, assume that thermometer readings are normally distributed with a mean of 0oC and a standard deviation of 1.00oC. A thermometer is randomly selected and tested, find the probability of each reading. (The given values are in Celsius degrees.) If using technology instead of Table A-2, round answers to four decimal places. 9. Less than 2.39 10. Greater than 1.35 11. Between 0.14 and 2.57 12. Between -2.33 and 1.33 13. Less...
Assume that the readings on the thermometers are normally distributed with a mean of 0 Celsius...
Assume that the readings on the thermometers are normally distributed with a mean of 0 Celsius and a standard deviation of 0 1.00 Celsius. A thermometer is randomly selected and tested. In each case, draw a sketch, and find the probability of each reading. (The given values are in Celsius degrees.) a. Less than −1.75 . b. Greater than 1.685 c. Between 0.60 and 1.50 d. P( −1.82 < Z <1.82 )
Assume that thermometer readings are normally distributed with a mean of 0degreesC and a standard deviation...
Assume that thermometer readings are normally distributed with a mean of 0degreesC and a standard deviation of 1.00 degrees C. A thermometer is randomly selected and tested. For the case​ below, draw a​ sketch, and find the probability of the reading.​ (The given values are in Celsius​ degrees.) Between 1.00 and 2.25 What is the probability of getting a reading between 1.00 and 2.25
Assume that the readings on the thermometers are normally distributed with a mean of 0 Celsius...
Assume that the readings on the thermometers are normally distributed with a mean of 0 Celsius and a standard deviation of 1.00 Celsius. A thermometer is randomly selected and tested. In each case, draw a sketch, and find the probability of each reading. (The given values are in Celsius degrees.) A. Less than -1.24 B. Greater than 1.645 C. Between 0.59 and 1.51 D. P (Z <-2.575 or Z > 2.575) Please show all work as if inputting into a...
1) Assume that thermometer readings are normally distributed with a mean of 0degreesC and a standard...
1) Assume that thermometer readings are normally distributed with a mean of 0degreesC and a standard deviation of 1.00degreesC. A thermometer is randomly selected and tested. For the case​ below, draw a​ sketch, and find the probability of the reading.​ (The given values are in Celsius​ degrees.) Between 1.00 and 2.00 Choose the correct graph below. a) z=1.00 z=2.00 b) z=1.00 z=2.00 c) z=1.00 z=2.00 2) Assume that a randomly selected subject is given a bone density test. Those test...
Assume that thermometer readings are normally distributed with a mean of 0 degrees°C and a standard...
Assume that thermometer readings are normally distributed with a mean of 0 degrees°C and a standard deviation of 1.00 degrees°C. A thermometer is randomly selected and tested. The probability of getting a reading between 0.25 and 1.25 is?
Using the Standard Normal Distribution. Assume that the readings on scientific thermometers are normally distributed with...
Using the Standard Normal Distribution. Assume that the readings on scientific thermometers are normally distributed with a mean of 0 °C and a standard deviation of 1.00 °C. A thermometer is randomly selected and tested. In each case, draw a sketch, and find the probability of each reading in degrees Celsius A) Less than 2.75 B) Between 1.50 and 2.50
Assume that thermometer readings are normally distributed with a mean of 0degreesC and a standard deviation...
Assume that thermometer readings are normally distributed with a mean of 0degreesC and a standard deviation of 1.00degreesC. A thermometer is randomly selected and tested. For the case​ below, draw a​ sketch, and find the probability of the reading.​ (The given values are in Celsius​ degrees.) Between 1.50 and 2.25
Assume that thermometer reading are normally distributed with a mean of 0°C and a standard deviation...
Assume that thermometer reading are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. (a) Find the probability of a reading less than -2.75. (b) Find the probability of a reading greater than 2.33 (c) Find the probability of a reading between -2.87 and 1.34 (d) Find the 96th percentile
Assume that the readings at freezing on a bundle of thermometers are normally distributed with a...
Assume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading less than -1.503°C. P(Z<−1.503)=P(Z<-1.503)=