In the following exercises, assuming that the thermometer readings are normally distributed, with a mean of 0 celsius and a standard deviation of 1.00 celsius. A thermometer is randomly selected and tested. In each case, calculate the probability of each reading.
to. greater than 1.25
b. greater than -1.75
c. less than 2.50
d. less than -3.75
and. between -2.45 and -2.00
F. between -1.00 and 4.00
g. P (-1.96 <z <1.96)
Solution :
Given that,
Using standard normal table ,
a.
P(z > 1.25) = 1 - P(z < 1.25) = 1 - 0.8944 = 0.1056
b.
P(z > -1.75) = 1 - P(z < -1.75) = 1 - 0.0401 = 0.9599
c.
P(z < 2.50) = 0.9938
d.
P(z < -3.75) = 0.0001
and
P(-2.45 < z < -2.00)
= P(z < -2.00) - P(z < -2.45)
= 0.0228 - 0.0071
= 0.0217
P(-2.45 < z < -2.00) = 0.0217
f
P(-1.00 < z < 4.00)
= P(z < 4.00) - P(z < -1.00)
= 1 - 0.1587
= 0.8413
P(-1.00 < z < 4.00) = 0.8413
g
P(-1.96 < z < 1.96)
= P(z < 1.96) - P(z < -1.96)
= 0.975 - 0.025
= 0.95
P(-1.96 < z < 1.96) = 0.95
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