We're analyzing the proportion of people watching TV in a given night. In our sample, we have 35 out of 100 people watching TV. We're testing the null hypothesis that 50% of the entire population which we sampled watched TV that night, and got a p-value of 0.00352. What is the conclusion that we make if our significance level was 0.05?
reject the null hypothesis
Based on the above, what would be the p-value associated with the null hypothesis that more than 50% of the people watch TV on this night?
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Solution :
This is the right tailed test .
The null and alternative hypothesis is
H0 : p = 0.50
Ha : p 0.50
n = 100
x =35
= x / n = 35 / 100 =0.35
P0 = 0.50
1 - P0 = 1 - 0.50 = 0.50
Test statistic = z
= - P0 / [P0 * (1 - P0 ) / n]
=0.35 - 0.50 / [(0.50*0.50) / 100 ]
= - 3.00
Test statistic = z = - 3.00
P(z > - 3.00 ) = 1 - P(z < ) = 1 - 0.0013
P-value = 0.9987
= 0.05
P-value >
0.9987 > 0.05
Fail to reject the null hypothesis .
There is insufficient evidence to suggest that
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