Do female college students spend more time than male college
students watching TV? This was one of the questions investigated by
the authors of an article. Each student in a random sample of 46
male students at a university in England and each student in a
random sample of 38 female students from the same university kept a
diary of how he or she spent time over a three-week period.
For the sample of males, the mean time spent watching TV per day
was 68.3 minutes and the standard deviation was 67.5 minutes. For
the sample of females, the mean time spent watching TV per day was
93.3 minutes and the standard deviation was 89.1 minutes. Is there
convincing evidence that the mean time female students at this
university spend watching TV is greater than the mean time for male
students? Test the appropriate hypotheses using
α = 0.05.
(Use a statistical computer package to calculate the P-value. Use μmales − μfemales. Round your test statistic to two decimal places, your df down to the nearest whole number, and your P-value to three decimal places.)
t | = |
df | = |
P-value | = |
State your conclusion.
Fail to reject H0. We do not have convincing evidence that the mean time female students at this university spend watching TV is greater than the mean time for male students.
Reject H0. We have convincing evidence that the mean time female students at this university spend watching TV is greater than the mean time for male students.
Reject H0. We do not have convincing evidence that the mean time female students at this university spend watching TV is greater than the mean time for male students.
Fail to reject H0. We have convincing evidence that the mean time female students at this university spend watching TV is greater than the mean time for male students.
Two-Sample T-Test and CI
Method
μ₁: mean of Males |
µ₂: mean of Females |
Difference: μ₁ - µ₂ |
Descriptive Statistics
Sample | N | Mean | StDev | SE Mean |
Sample 1 | 46 | 68.3 | 67.5 | 10 |
Sample 2 | 38 | 93.3 | 89.1 | 14 |
Estimation for Difference
Difference | 95% Upper Bound for Difference |
-25.0 | 4.3 |
Test
Null hypothesis | H₀: μ₁ - µ₂ = 0 |
Alternative hypothesis | H₁: μ₁ - µ₂ < 0 |
T-Value | DF | P-Value |
-1.42 | 67 | 0.079 |
Since P-value is greater than level of significance, i.e. 0.079 > 0.05, we don't have sufficient evidence to reject the null hypothesis.
Conclusion: Fail to reject H0. We do not have convincing evidence that the mean time female students at this university spend watching TV is greater than the mean time for male students.
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