Question

Your friend tells you that the proportion of active Major League Baseball players who have a...

Your friend tells you that the proportion of active Major League Baseball players who have a batting average greater than .300 is different from 0.71, a claim you would like to test. The hypotheses for this test are Null Hypothesis: p = 0.71, Alternative Hypothesis: p ≠ 0.71. If you randomly sample 23 players and determine that 14 of them have a batting average higher than .300, what is the test statistic and p-value?

Homework Answers

Answer #1

= 14/23 = 0.61

The test statistic z = ( - p)/sqrt(p(1 - p)/n)

                              = (0.61 - 0.71)/sqrt(0.71 * (1 - 0.71)/23)

                              = -1.06

P-value = 2 * P(Z < -1.06)

            = 2 * 0.1446

            = 0.2892

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Your friend tells you that the proportion of active Major League Baseball players who have a...
Your friend tells you that the proportion of active Major League Baseball players who have a batting average greater than .300 is different from 0.64, a claim you would like to test. The hypotheses for this test are Null Hypothesis: p = 0.64, Alternative Hypothesis: p ≠ 0.64. If you randomly sample 30 players and determine that 24 of them have a batting average higher than .300, what is the test statistic and p-value?
Your friend tells you that the proportion of active Major League Baseball players who have a...
Your friend tells you that the proportion of active Major League Baseball players who have a batting average greater than .300 is different from 0.77, a claim you would like to test. The hypotheses for this test are Null Hypothesis: p = 0.77, Alternative Hypothesis: p ≠ 0.77. If you randomly sample 24 players and determine that 19 of them have a batting average higher than .300, what is the test statistic and p-value? Question 9 options: 1) Test Statistic:...
Your friend tells you that the proportion of active Major League Baseball players who have a...
Your friend tells you that the proportion of active Major League Baseball players who have a batting average greater than .300 is different from 0.74, a claim you would like to test. The hypotheses here are Null Hypothesis: p = 0.74, Alternative Hypothesis: p ≠ 0.74. If you take a random sample of players and calculate p-value for your hypothesis test of 0.9623, what is the appropriate conclusion? Conclude at the 5% level of significance. Question 15 options: 1) We...
Question 10 (1 point) Your friend tells you that the proportion of active Major League Baseball...
Question 10 (1 point) Your friend tells you that the proportion of active Major League Baseball players who have a batting average greater than .300 is greater than 0.51, a claim you would like to test. If you conduct a hypothesis test, what will the null and alternative hypotheses be? Question 10 options: 1) HO: p ≥ 0.51 HA: p < 0.51 2) HO: p < 0.51 HA: p ≥ 0.51 3) HO: p ≤ 0.51 HA: p > 0.51...
A suggestion is made that the proportion of people who have food allergies and/or sensitivities is...
A suggestion is made that the proportion of people who have food allergies and/or sensitivities is 0.42. You believe that the proportion is actually greater than 0.42. The hypotheses for this test are Null Hypothesis: p ≤ 0.42, Alternative Hypothesis: p > 0.42. If you select a random sample of 25 people and 17 have a food allergy and/or sensitivity, what is your test statistic and p-value? Question 8 options: 1) Test Statistic: 2.634, P-Value: 0.004 2) Test Statistic: -2.634,...
A sports analyst wants to estimate the true proportion of baseball players in the National League...
A sports analyst wants to estimate the true proportion of baseball players in the National League with a batting average of 0.400 or greater. They want to be 98% confident with a margin of error of 5%. How many players should be sampled if: No prior estimate of p is available? A previous study estimated that the proportion was 24%?
A student at a university wants to determine if the proportion of students that use iPhones...
A student at a university wants to determine if the proportion of students that use iPhones is different from 0.45. If the student conducts a hypothesis test, what will the null and alternative hypotheses be? 1) HO: p ≤ 0.45 HA: p > 0.45 2) HO: p > 0.45 HA: p ≤ 0.45 3) HO: p = 0.45 HA: p ≠ 0.45 4) HO: p ≠ 0.45 HA: p = 0.45 5) HO: p ≥ 0.45 HA: p < 0.45...
The salaries of a random sample of 50 major league baseball players for 2012 are 3.44...
The salaries of a random sample of 50 major league baseball players for 2012 are 3.44 million dollars. Assuming the distribution of salaries for all major league baseball players is normally distributed with a standard deviation of $0.712 million, test the claim that the mean salary of major league baseball players is less than 4 million dollars. Use a significance level of 0.05. What is the test statistic? What is the critical value? What is the p-value? What is the...
Based on past data, the producers of Ice Mountain bottled water knew that the proportion of...
Based on past data, the producers of Ice Mountain bottled water knew that the proportion of people who preferred Ice Mountain to tap water was 0.71. To see how consumer perception of their product changed, they decided to conduct a survey. Of the 134 respondents, 97 indicated that they preferred Ice Mountain to the tap water in their homes. The 90% confidence interval for this proportion is ( 0.6604 , 0.7874 ). What is the best conclusion of those listed...
Based on past data, the proportion of Major League Baseball (MLB) players who bat left handed...
Based on past data, the proportion of Major League Baseball (MLB) players who bat left handed was 0.481. You are interested to see if this is still the case. You conduct a sample of 23 players and find that 10 are left handed hitters. The 95% confidence interval is ( 0.2322 , 0.6374 ). What is the best conclusion of those listed below? Question 6 options: 1) The confidence interval does not provide enough information to form a conclusion. 2)...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT