Question

# A suggestion is made that the proportion of people who have food allergies and/or sensitivities is...

A suggestion is made that the proportion of people who have food allergies and/or sensitivities is 0.42. You believe that the proportion is actually greater than 0.42. The hypotheses for this test are Null Hypothesis: p ≤ 0.42, Alternative Hypothesis: p > 0.42. If you select a random sample of 25 people and 17 have a food allergy and/or sensitivity, what is your test statistic and p-value?

Question 8 options:

 1) Test Statistic: 2.634, P-Value: 0.004
 2) Test Statistic: -2.634, P-Value: 0.996
 3) Test Statistic: -2.634, P-Value: 0.004
 4) Test Statistic: 2.634, P-Value: 0.996
 5) Test Statistic: 2.634, P-Value: 0.008

Your friend tells you that the proportion of active Major League Baseball players who have a batting average greater than .300 is different from 0.79, a claim you would like to test. The hypotheses here are Null Hypothesis: p = 0.79, Alternative Hypothesis: p ≠ 0.79. If you take a random sample of players and calculate p-value for your hypothesis test of 0.0037, what is the appropriate conclusion? Conclude at the 5% level of significance.

Question 9 options:

 1) We did not find enough evidence to say a significant difference exists between the proportion of MLB players that have an average higher than .300 and 0.79
 2) The proportion of active MLB players that have an average higher than .300 is significantly less than 0.79.
 3) The proportion of active MLB players that have an average higher than .300 is significantly larger than 0.79.
 4) The proportion of active MLB players that have an average higher than .300 is equal to 0.79.
 5) The proportion of active MLB players that have an average higher than .300 is significantly different from 0.79.

Your friend tells you that the proportion of active Major League Baseball players who have a batting average greater than .300 is greater than 0.51, a claim you would like to test. The hypotheses here are Null Hypothesis: p ≤ 0.51, Alternative Hypothesis: p > 0.51. If you take a random sample of players and calculate p-value for your hypothesis test of 0.9482, what is the appropriate conclusion? Conclude at the 5% level of significance.

Question 10 options:

 1) The proportion of active MLB players that have an average higher than .300 is significantly larger than 0.51.
 2) We did not find enough evidence to say the proportion of active MLB players that have an average higher than .300 is less than 0.51.
 3) The proportion of active MLB players that have an average higher than .300 is less than or equal to 0.51.
 4) We did not find enough evidence to say a significant difference exists between the proportion of MLB players that have an average higher than .300 and 0.51
 5) We did not find enough evidence to say the proportion of active MLB players that have an average higher than .300 is larger than 0.51.

Solution-8:

Hp:p<=0.42

Ha:p>0.42

p^=x/n=17/25=0.68

In ti 83 cal

go to

STAT>TESTS>1 PROP Z TEST\

z=2.6339

p=0.0042

 1) Test Statistic: 2.634, P-Value: 0.004

olution-9

Ho:p=0.79

Ha: p not =0.79

p=0.0037

p<0.05

reject Ho

 5) The proportion of active MLB players that have an average higher than .300 is significantly different from 0.79.

Solution-10:

Ho:p<=0.51

Ha:p>0.51

p=0.9482

p>0.05

Fail to reject Ho.

 5) We did not find enough evidence to say the proportion of active MLB players that have an average higher than .300 is larger than 0.51.

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