Your friend tells you that the proportion of active Major League Baseball players who have a batting average greater than .300 is different from 0.74, a claim you would like to test. The hypotheses here are Null Hypothesis: p = 0.74, Alternative Hypothesis: p ≠ 0.74. If you take a random sample of players and calculate pvalue for your hypothesis test of 0.9623, what is the appropriate conclusion? Conclude at the 5% level of significance.
Question 15 options:









Answer:
Given,
Test statistic, z = 0.9623
By observing we can say that It is a two tailed test.
Here it is 5% Significance level,
i.e.,
= 0.05
Now the Pvalue for a two tailed test =2*(1  NORM.S.DIST(ABS(0.9623), TRUE)
P value = 0.3359
P  value = 0.3359 > 0.05 here it is greater than the significance level, so we fail to reject the null hypothesis Ho.
So we can conclude that Option C is correct answer.
i.e.,
The proportion of active MLB players that have an average higher than .300 is equal to 0.74.
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