Question

Listed below are systolic blood pressure measurements​ (in mm​ Hg) obtained from the same woman. Find the regression​ equation, letting the right arm blood pressure be the predictor​ (x) variable. Find the best predicted systolic blood pressure in the left arm given that the systolic blood pressure in the right arm is 85 mm Hg. Use a significance level of 0.05

Right Arm	102	101	95	80	81
Left Arm	175	168	144	143	144

1. The regression equation is y =_____________+ ______________x.​(Round to one decimal place as​ needed.)

2. Given that the systolic blood pressure in the right arm is 85 mm​ Hg, the best predicted systolic blood pressure in the left arm is __________ mm Hg. (Round to one decimal place as​ needed.)

Answer 1

X	Y	XY	X^2	Y^2
102	175	17850	10404	30625
101	168	16968	10201	28224
95	144	13680	9025	20736
80	143	11440	6400	20449
81	144	11664	6561	20736

From the above table and formula we get the value are as:

n	5
sum(XY)	71602.00
sum(X)	459.00
sum(Y)	774.00
sum(X^2)	42591.00
sum(Y^2)	120770.00

b	1.2067
a	44.0264

The regression equation is ycap = a +bx

ycap =44.0 + 1.2x

b)

when x = 85

Predicted value = 44 + 1.2 * 85

= 146.0

Given that the systolic blood pressure in the right arm is 85 mm​ Hg, the best predicted systolic blood pressure in the left arm is 146.0mm Hg