Listed below are systolic blood pressure measurements (in mm Hg) obtained from the same woman. Find the regression equation, letting the right arm blood pressure be the predictor (x) variable. Find the best predicted systolic blood pressure in the left arm given that the systolic blood pressure in the right arm is 100 mm Hg. Use a significance level of 0.05. Right Arm 102 101 94 79 79 Left Arm 175 170 145 146 144
X | Y | XY | X^2 | Y^2 |
102 | 175 | 17850 | 10404 | 30625 |
101 | 170 | 17170 | 10201 | 28900 |
94 | 145 | 13630 | 8836 | 21025 |
79 | 146 | 11534 | 6241 | 21316 |
79 | 144 | 11376 | 6241 | 20736 |
Predicted Y = a +bx
From the above table and formula we get the value are as:
n | 5 |
sum(XY) | 71560.00 |
sum(X) | 455.00 |
sum(Y) | 780.00 |
sum(X^2) | 41923.00 |
sum(Y^2) | 122602.00 |
b | 1.1197 |
a | 54.1081 |
ycap= a +bx
Regression equation:
ycap= 54.1081 + 1.1197x
when x = 100
Predicted value = 54.1081 + 1.1197 * 100
= 166.0781
= approx 166
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