null Hypothesis: Ho: p= | 0.260 | |||
alternate Hypothesis: Ha: p ≠ | 0.260 | |||
for 0.05 level and two tailed test , critical z= | 1.96 | (from excel:normsinv(0.025) | ||
Decision rule : reject Ho if absolute value of test statistic |z|>1.96 |
sample success x = | 112 | ||
sample size n = | 400 | ||
std error σp =√(p*(1-p)/n) = | 0.0219 | ||
sample prop p̂ = x/n=112/400= | 0.2800 | ||
z =(p̂-p)/σp=(0.28-0.26)/0.28= | 0.91 |
since test statistic does not falls in rejection region we fail to reject null hypothesis |
we do not have have sufficient evidence to conclude that population proportion differs from 0.26. |
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