Question

According to a recent​ report, 44​% of college student internships are unpaid. A recent survey of...

According to a recent​ report, 44​% of college student internships are unpaid. A recent survey of 100 college interns at a local university found that 60 had unpaid internships.

a. Use the​ five-step p-value approach to hypothesis testing and a 0.01 level of significance to determine whether the proportion of college interns that had unpaid internships is different from 0.44.

b. Assume that the study found that 50 of the 100 college interns had unpaid internships and repeat​ (a). Are the conclusions the​ same?

Homework Answers

Answer #1

Answer;

a)

Given,

sample proportion p^ = x/n = 60/100 = 0.60

Ho ; p = 0.44

Ha : p != 0.44

test statistic z = (p^ - p)/sqrt(pq/n)

substitute values

= (0.60 - 0.44) / sqrt(0.60*0.40/100)

= 3.27

P value = 0.0010755 [since from z table]

= 0.001

Here p value < alpha, so we reject Ho.

So there is sufficient evidence to support the claim.

b)

sample proportion p^ = x/n = 50/100 = 0.5

test statistic z = (p^ - p)/sqrt(pq/n)

substitute values

= (0.50 - 0.44) / sqrt(0.50*0.50/100)

= 1.2

P value = 0.2301393 [since from z table]

= 0.2301

Here p value > alpha, so we fail to reject Ho.

So there is no sufficient evidence to support the claim.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
According to a recent​ report, 45​% of college student internships are unpaid. A recent survey of...
According to a recent​ report, 45​% of college student internships are unpaid. A recent survey of 120 college interns at a local university found that 73 had unpaid internships. a. Use the​ five-step p-value approach to hypothesis testing and a 0.01 level of significance to determine whether the proportion of college interns that had unpaid internships is different from 0.45. b. Assume that the study found that 66 of the 120 college interns had unpaid internships and repeat​ (a). Are...
According to a recent report, 45% of college student internships are unpaid. A recent survey of...
According to a recent report, 45% of college student internships are unpaid. A recent survey of 100 college interns at a local university found that 48 had unpaid internships. a. Use the five-step p-value approach to hypothesis testing and a 0.01 level of significance to determine whether the proportion of college interns that had unpaid internships is different from 0.45 b. Assume that the study found that 60 out of the 100 college interns had unpaid internships and repeat (a)....
According to a recent​ report, 46​% of college student internships are unpaid. A recent survey of...
According to a recent​ report, 46​% of college student internships are unpaid. A recent survey of 120 college interns at a local university found that 68 had unpaid internships. a. Use the​ five-step p-value approach to hypothesis testing and a 0.05 level of significance to determine whether the proportion of college interns that had unpaid internships is different from 0.46. b. Assume that the study found that 57 of the 120 college interns had unpaid internships and repeat​ (a). Are...
35. According to a recent​ report, 48​% of college student internships are unpaid. A recent survey...
35. According to a recent​ report, 48​% of college student internships are unpaid. A recent survey of 60 college interns at a local university found that 40 had unpaid internships. a. Use the​ five-step p-value approach to hypothesis testing and a 0.05 level of significance to determine whether the proportion of college interns that had unpaid internships is different from 0.48. Let π be the population proportion. Determine the null​ hypothesis and the alternative​ hypothesis. What is the test​ statistic?...
In a recent survey of 100 college students, 49% had received the HPV vaccine. Construct a...
In a recent survey of 100 college students, 49% had received the HPV vaccine. Construct a 99% confidence interval for the proportion of college students who have received the vaccine. - Report the interval as a complete sentence in the context of the problem. - Would a 95% confidence interval be narrower or wider? Why? - Is it possible that the true proportion of vaccinate college students is over 50%? Why or why not?
According to the Oxnard College Student Success Committee report in the previous year, we believe that...
According to the Oxnard College Student Success Committee report in the previous year, we believe that 21% of students struggle in their classes because they don't spend more than 8 hours studying independently outside of a 4-unit class. For this year, you would like to obtain a new sample to estimate the proportiton of all Oxnard students who struggle in their classes because they don't study enough outside of the classrooms. You would like to be 99% confident that your...
According to the Oxnard College Student Success Committee report in the previous year, we believe that...
According to the Oxnard College Student Success Committee report in the previous year, we believe that 23% of students struggle in their classes because they don't spend more than 8 hours studying independently outside of a 4-unit class. For this year, you would like to obtain a new sample to estimate the proportiton of all Oxnard students who struggle in their classes because they don't study enough outside of the classrooms. You would like to be 90% confident that your...
Each year over 1,000 college students die in alcohol-related deaths, often in cases that involve binge...
Each year over 1,000 college students die in alcohol-related deaths, often in cases that involve binge drinking. Harvard School of Public Health reported in 2004 that 44% of college students are binge drinkers. In an informal anonymous survey conducted in a statistics class shortly after the Harvard report was released, students were asked: "In the past two weeks, have you had (males) more than five alcoholic drinks on one occasion? (females) more than four alcoholic drinks on one occasion?" [This...
1. According to a recent report, 38% of adults wait until they are 30 years of...
1. According to a recent report, 38% of adults wait until they are 30 years of age or older to get married for the first time. A researcher believes this claimed value is too low. He gathers data in order to test the hypotheses Ho: p = 0.38 vs. Ha: p > 0.38. In these hypotheses, what does p represent? A. The sample proportion B. The population proportion C. The p-value D. The sample mean E. The population mean 2....
BIOS 376 Homework 7 1. A professor claims that the mean IQ for college students is...
BIOS 376 Homework 7 1. A professor claims that the mean IQ for college students is 92. He collects a random sample of 85 college students to test this claim and the mean IQ from the sample is 84. (a) What are the null and alternative hypotheses to test the initial claim? (1 pt) (b) Using R, compute the test statistic. Assume the population standard deviation of IQ scores for college students is 17.6 points. (1 pt) (c) Using R,...