You need to estimate the mean number of travel days per year for outside salespeople. The mean of a small pilot study was 140 days, with a standard deviation of 24 days. If you must estimate the population mean within 4 days, how many outside salespeople should you sample? Use the 99% confidence level.
Solution :
Given that,
standard deviation = =24
margin of error = E = 4
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576
Sample size = n = ((Z/2 * ) / E)2
= ((2.576 * 24) / 4)2
= 239
Sample size =239
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