You want to estimate the mean number of friends for all Facebook users. How many users must be included in the sample if you want to be 95% confident that the sample mean is within seven friends of the population mean? Assume the population standard deviation is 53.
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Solution
standard deviation =s = =53
Margin of error = E = 7
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96 ( Using z table ( see the 0.025 value in standard normal (z) table corresponding z value is 1.96 )
sample size = n = [Z/2* / E] 2
n = ( 1.96* 53/7 )2
n =220.22
Sample size = n =221
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