Question

You wish to estimate the mean number of travel days per year for salespeople. The mean...

You wish to estimate the mean number of travel days per year for salespeople. The mean of a small pilot study was 150 days, with a standard deviation of 42 days.

If you want to estimate the population mean within 6 days, how many salespeople should you sample? Use the 99% confidence level. (Use z Distribution Table.) (Round up your answer to the next whole number.)

Homework Answers

Answer #1

Solution :

Given that,

standard deviation =  σ =42

Margin of error = E = 6

At 99% confidence level the z is,

= 1 - 99%

= 1 - 0.99 = 0.01

/2 = 0.005

Z/2  = 2.576

sample size = n = [ Z/2 *  σ/ E]2

n = ( 2.576*42 /6 )2

n =325.15

Sample size = n =326

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
You need to estimate the mean number of travel days per year for outside salespeople. The...
You need to estimate the mean number of travel days per year for outside salespeople. The mean of a small pilot study was 140 days, with a standard deviation of 15 days. If you must estimate the population mean within 3 days, how many outside salespeople should you sample? Use the 99% confidence level. (Round the intermediate calculation to 3 decimal places. Round the final answer to the nearest whole number.)                                    Number of outside salespeople           
You need to estimate the mean number of travel days per year for outside salespeople. The...
You need to estimate the mean number of travel days per year for outside salespeople. The mean of a small pilot study was 140 days, with a standard deviation of 11 days. If you must estimate the population mean within 4 days, how many outside salespeople should you sample? Use the 99% confidence level. (Round the intermediate calculation to 3 decimal places. Round the final answer to the nearest whole number.)                                    Number of outside salespeople           
You need to estimate the mean number of travel days per year for outside salespeople. The...
You need to estimate the mean number of travel days per year for outside salespeople. The mean of a small pilot study was 140 days, with a standard deviation of 24 days. If you must estimate the population mean within 4 days, how many outside salespeople should you sample? Use the 99% confidence level.
You need to estimate the mean number of travel days per year for outside salespeople. The...
You need to estimate the mean number of travel days per year for outside salespeople. The mean of a small pilot study was 160 days, with a standard deviation of 19 days. If you must estimate the population mean within 2 days, how many outside salespeople should you sample? Use the 98% confidence level. (Round the intermediate calculation to 3 decimal places. Round the final answer to the nearest whole number.) Number of outside salespeople
You need to estimate the mean number of travel days per year for outside salespeople. The...
You need to estimate the mean number of travel days per year for outside salespeople. The mean of a small pilot study was 160 days, with a standard deviation of 25 days. If you must estimate the population mean within 3 days, how many outside salespeople should you sample? Use the 98% confidence level.
A survey is being planned to determine the mean amount of time corporation executives watch television....
A survey is being planned to determine the mean amount of time corporation executives watch television. A pilot survey indicated that the mean time per week is 15 hours, with a standard deviation of 2.5 hours. It is desired to estimate the mean viewing time within 30 minutes. The 99% level of confidence is to be used. (Use z Distribution Table.) How many executives should be surveyed? (Round your z-score to 2 decimal places and round up your final answer...
A researcher wishes to estimate the average number of minutes per day a person spends on...
A researcher wishes to estimate the average number of minutes per day a person spends on the Internet. How large a sample must she select if she wishes to be 99% confident that the population mean is within 10 minutes of the sample mean? Assume the population standard deviation is 42 minutes. Round your final answer up to the next whole number
You want to obtain a sample to estimate a population mean. Based on previous evidence, you...
You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard deviation is approximately σ=35.3σ=35.3. You would like to be 95% confident that your estimate is within 0.1 of the true population mean. How large of a sample size is required? As in the reading, in your calculations: --Use z = 1.645 for a 90% confidence interval --Use z = 2 for a 95% confidence interval --Use z = 2.576 for...
You want to obtain a sample to estimate a population mean. Based on previous evidence, you...
You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard deviation is approximately σ=59.1σ=59.1. You would like to be 90% confident that your estimate is within 5 of the true population mean. How large of a sample size is required? As in the reading, in your calculations: --Use z = 1.645 for a 90% confidence interval --Use z = 2 for a 95% confidence interval --Use z = 2.576 for...
A survey is being planned to determine the mean amount of time corporation executives watch television....
A survey is being planned to determine the mean amount of time corporation executives watch television. A pilot survey indicated that the mean time per week is 14 hours, with a standard deviation of 2.0 hours. It is desired to estimate the mean viewing time within 30 minutes. The 98% level of confidence is to be used. (Use z Distribution Table.) How many executives should be surveyed? (Round your z-score to 2 decimal places and round up your final answer...