You need to estimate the mean number of travel days per year for outside salespeople. The mean of a small pilot study was 160 days, with a standard deviation of 19 days. If you must estimate the population mean within 2 days, how many outside salespeople should you sample? Use the 98% confidence level. (Round the intermediate calculation to 3 decimal places. Round the final answer to the nearest whole number.) Number of outside salespeople
Solution :
Given that,
standard deviation = =19
Margin of error = E = 2
At 98% confidence level the z is ,
= 1 - 98% = 1 - 0.98 = 0.02
/ 2 = 0.02/ 2 = 0.01
Z/2 = Z0.01 = 2.326 ( Using z table )
sample size = n = [Z/2* / E] 2
n = ( 2.326*19 / 2 )2
n =488.2777
Sample size = n =488
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