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In a poll, 368 of 600 registered people intended to vote for Jim. With that information,...

In a poll, 368 of 600 registered people intended to vote for Jim. With that information, test the hypothesis at a 95% confidence level.

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Answer #1

Given

n = 600

x = 368

population proportion = p = x / n

p = 368 / 600

p = 0.6133 , 1-p = 0.3867

Standard error (S.E) =

S.E =

S.E = 0.0199

At 95% confidence =1 - 0.95 = 0.05

critical value at Z0.05 = 1.96

Margin of Error (E) = Crit value * S.E

= 1.96 * 0.0199 = 0.039

Confidence interval (C.I)= p E

C.I = 0.6133 0.039

= (0.5743 , 0.6523)

The  95% confidence interval is (0.5743 , 0.6523).

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