Question

A website reported that 29% of drivers 18 and older admitted to texting while driving in...

A website reported that 29% of drivers 18 and older admitted to texting while driving in 2009. In a random sample of 800 drivers 18 years and older drawn in​ 2010, 176 of the drivers said they texted while driving. Complete parts a through c below.

a. Construct a 95% confidence interval to estimate the actual proportion of people who texted while driving in 2010. A 95% confidence interval to estimate the actual proportion has a lower limit of nothing​​​​​​​ and an upper limit of​​​​​​​ nothing. ​(Round to three decimal places as​ needed.)

b. What is the margin of error for this​ sample?

The margin of error is nothing.______ (Round to three decimal places as​ needed.)

c. Is there any evidence that this proportion has changed since 2009 based on this​ sample?

Because the confidence interval found in part a includes?​​​​​​​ the reported proportion from​ 2009, this sample​​​​​​​ provides? evidence that this proportion has changed since then.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A website reported that 31% of drivers 18 and older admitted to texting while driving in...
A website reported that 31% of drivers 18 and older admitted to texting while driving in 2009. In a random sample of 400 drivers 18 years and older drawn in​ 2010, 92 of the drivers said they texted while driving. Complete parts a through c below. a. Construct a 90​% confidence interval to estimate the actual proportion of people who texted while driving in 2010.A 90​% confidence interval to estimate the actual proportion has a lower limit of nothing and...
A website reported that 28 % of drivers 18 and older admitted to texting while driving...
A website reported that 28 % of drivers 18 and older admitted to texting while driving in 2009. In a random sample of 400 drivers 18 years and older drawn in 2010, 109 of the drivers said they texted while driving. Complete parts a through c below. a. Construct a 90 % confidence interval to estimate the actual proportion of people who texted while driving in 2010. A 90 % confidence interval to estimate the actual proportion has a lower...
According to a census? bureau, 13.513.5?% of the population in a certain country changed addresses from...
According to a census? bureau, 13.513.5?% of the population in a certain country changed addresses from 2008 to 2009. In? 2010, 3131 out of a random sample of 400400 citizens of this country said they changed addresses during the previous year? (in 2009). Complete parts a through c below. a. Construct a 9595?% confidence interval to estimate the actual proportion of people who changed addresses from 2009 to 2010.A 9595?% confidence interval to estimate the actual proportion has a lower...
It was reported that 63​% of individual tax returns were filed electronically in 2012. A random...
It was reported that 63​% of individual tax returns were filed electronically in 2012. A random sample of 325 tax returns from 2013 was selected. From this​ sample, 237 were filed electronically. Complete parts a through c below. a. Construct a 95​% confidence interval to estimate the actual proportion of taxpayers who filed electronically in 2013. A 95​% confidence interval to estimate the actual proportion has a lower limit of nothing and an upper limit of nothing. ​(Round to three...
According to a census​ bureau, 11.5​% of the population in a certain country changed addresses from...
According to a census​ bureau, 11.5​% of the population in a certain country changed addresses from 2008 to 2009. In​ 2010, 26 out of a random sample of 400 citizens of this country said they changed addresses during the previous year​ (in 2009). Complete parts a through c below. a. Construct a 95​% confidence interval to estimate the actual proportion of people who changed addresses from 2009 to 2010. A 95​% confidence interval to estimate the actual proportion has a...
According to a census​ bureau,12.5​% of the population in a certain country changed addresses from 2008...
According to a census​ bureau,12.5​% of the population in a certain country changed addresses from 2008 to 2009. In​ 2010,14 out of a random sample of 200 citizens of this country said they changed addresses during the previous year​ (in 2009). Complete parts a through c below. A) Construct a 9999​% confidence interval to estimate the actual proportion of people who changed addresses from 2009 to 2010. A) 99​% confidence interval to estimate the actual proportion has a lower limit...
The IRS reported that 62% of individual tax returns were filed electronically in 2008. A random...
The IRS reported that 62% of individual tax returns were filed electronically in 2008. A random sample of 225 tax returns from 2010 was selected. From this sample, 163 were filed electronically. a) Construct a 95% confidence interval to estimate the actual proportion of taxpayers who filed electronically in 2010. b) What is the margin of error for this sample? c) Is there any evidence that this proportion has changed since 2008 based on this sample? Please spell the steps...
A consumer agency wants to estimate the proportion of all drivers who wear seat belts while...
A consumer agency wants to estimate the proportion of all drivers who wear seat belts while driving. What is the most conservative estimate of the sample size that would limit the margin of error to within 038 of the population proportion for a 99% confidence interval? Round your answer up to the nearest whole number. n=
The Centers for Disease Control reported the percentage of people 18 years of age and older...
The Centers for Disease Control reported the percentage of people 18 years of age and older who smoke (CDC website, December 14, 2014). Suppose that a study designed to collect new data on smokers and nonsmokers uses a preliminary estimate of the proportion who smoke of .35 : A sample of 2185 is taken with a margin of error of .02 by using 95% confidence. The sample size recommendation of 2185 finds 520 smokers. A point estimate of the proportion...
The Centers for Disease Control reported the percentage of people 18 years of age and older...
The Centers for Disease Control reported the percentage of people 18 years of age and older who smoke (CDC website, December 14, 2014). Suppose that a study designed to collect new data on smokers and nonsmokers uses a preliminary estimate of the proportion who smoke of .29. a. How large a sample should be taken to estimate the proportion of smokers in the population with a margin of error of .02 (to the nearest whole number)? Use 95% confidence. b....
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT