Question

According to a census​ bureau,12.5​% of the population in a certain country changed addresses from 2008 to 2009. In​ 2010,14 out of a random sample of 200 citizens of this country said they changed addresses during the previous year​ (in 2009). Complete parts a through c below.

A)

Construct a

9999​%

confidence interval to estimate the actual proportion of people who changed addresses from 2009 to 2010.

A) 99​% confidence interval to estimate the actual proportion has a lower limit of _ and an upper limit of _.

B)  What is the margin of error for this​ sample?

The margin of error is

C)

Is there any evidence that this proportion has changed since 2009 based on this​ sample?

Because the confidence interval found in part a

▼

includes

does not include

the reported proportion from​ 2009, this sample

▼

does not provide

provides

evidence that this proportion has changed since then.

Answer 1