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A consumer agency wants to estimate the proportion of all drivers who wear seat belts while...

A consumer agency wants to estimate the proportion of all drivers who wear seat belts while driving. What is the most conservative estimate of the sample size that would limit the margin of error to within 038 of the population proportion for a 99% confidence interval? Round your answer up to the nearest whole number.

n=

Math   Statistics-And-Probability   
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Answer #1

ANSWER:

Given that,

= 0.5

1 - = 1 - 0.5 = 0.5

margin of error = E =0.38

At 99% confidence level the z is,

= 1 - 99%

= 1 - 0.99 = 0.01

/2 = 0.005

Z/2 = 2.576 ( Using z table )

Sample size = n = (Z/2 / E)2 * * (1 - )

= (2.576 / 0.38)2 * 0.5 * 0.5

=12

Sample size = 12

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