A calibration curve is measured and the equation is y = 35.3 x + 0.85.
A solution with a concentration of 0.100 M is run by the method five times and the standard deviation of the result is found to be 0.032.
What is the analytical sensitivity at a concentration of 0.100 M?
a. 0.85
b. 42
c. 1100
d. 35.3
the answer is C, please explain why and why other answers are wrong!
Analytical sensitivity, =slope/standard deviation=m/Ss =35.3/0.032 =1103.125 rounded to 1100.
Thus, option C. is correct.
Option A. 0.85 is the Y-intercept, i.e., it is the value of Y when X =0. It's not Analytical sensitivity.
Option B. 42 is incorrect because m/Ss 42
Option D. 35.3 is the slope(m) of the given calibration curve. It is called as calibration sensitivity. Thus, 35.3 is calibration sensitivity but not analytical sensitivity.
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