Use the normal distribution and the given sample results to complete the test of the given hypotheses. Assume the results come from a random sample and use a 5 % significance level
Test H *subscript*0:p=0.5 vs H *subscript*a: p>0.5 using sample results p(with the little hat)=0.64 with n=75
test statistic: =
p value =
conculusion: reject, or do not reject H*subscript* 0
Solution :
This is the right tailed test .
The null and alternative hypothesis is
H0 : p = 0.5
Ha : p > 0.5
n = 75
= x0.64
P0 = 0.5
1 - P0 = 1 - 0.5 = 0.5
z = - P0 / [P0 * (1 - P0 ) / n]
= 0.64 - 0.5 / [(0.5 * 0.5) / 75.64-.5]
= 2.425
Test statistic = 2.425
This is the right tailed test .
P(z > 2.425) = 1 - P(z < 2.425) = 1 - 0.9923 = 0.0077
P-value = 0.0077
= 0.05
P-value <
Reject the null hypothesis (H0)
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