Use the normal distribution and the given sample results to complete the test of the given hypotheses. Assume the results come from a random sample and use a 5% significance level.
Test H0 : p=0.25 vs Ha : p<0.25 using the sample results p^=0.17 with n=100
Round your answer for the test statistic to two decimal places,
and your answer for the p-value to three decimal places.
test statistic=
p value=
Solution
Null hypothesis,
Alternative hypothesis,
Level of significance,
= (0.17-0.25)/(sqrt(0.25*0.75/100))
= -1.85
P(Z<-1.85)
Using z table we find that the
=0.032
H:p=0.25
The value is less than given significance level 0.05, so we reject the null hypothesis and conclude that there is a insufficient evidence to support the claim that the proportion percentage is less than 0.25.
H:p<0.25
a=0.05
Calculate the test statistic. P-P. Z= p.(1 - p.) n
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