Use the normal distribution and the given sample results to complete the test of the given hypotheses. Assume the results come from a random sample and use a 5% significance level. Test H0 : p=0.5 vs Ha : p>0.5 using the sample results p^=0.56 with n=50 Round your answer for the test statistic to two decimal places, and your answer for the p-value to three decimal places.
Test statistic:
p-value:
Solution ;
Given that,
n = 50
= 0.56
P0 = 0.5
1 - P0 = 1 - 0.5 = 0.5
z = - P0 / [P0 * (1 - P0 ) / n]
= 0.56 - 0.5/ [(0.5 * 0.5) / 50]
= 0.85
Test statistic = 0.85
This is the right tailed test .
P(z > 0.80) = 1 - P(z < 0.85) = 1 - 0.8023 = 0.1977
P-value = 0.1977
= 0.05
P-value >
fail to Reject
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