A train and a bus arrive at the station at random between 9 A.M. and 10 A.M. The train stops for 10 minutes and the bus for x minutes. Find x so that the probability that the bus and the train will meet equals 0.5. Explain step by step solution with diagram.
There is total 60 minute time in which the train at the station for 10 minutes.
i.e. p(the train at the station) = 10/60 = 1/6
similarly
p(the bus at the station) = x/60 (since the bus stop at the station for x minutes)
we have to find the probability that both are at the station and which needs to be 0.5.
p(both the train and the bus at the station)=p(the train at the station)*p(the bus at the station)
0.5 = (1/6)*(x/6)
0.5=x/36
i.e. x = 0.5*36 = 18
That means, the bus stop at the station for 18 minutes so the probability that the bus and the train will meet equal 0.5.
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