Question
A sample of 160 results in 40 successes. [You may find it useful to reference the...
A sample of 160 results in 40 successes. [You may find it useful to reference the z table.]
a. Calculate the point estimate for the population proportion of successes. (Do not round intermediate calculations. Round your answer to 3 decimal places.)
b. Construct 95% and 99% confidence intervals for the population proportion. (Round intermediate calculations to at least 4 decimal places. Round "z" value and final answers to 3 decimal places.)
c. Can we conclude at 95% confidence that the population proportion differs from 0.310? (multiple choice)
No, since the confidence interval does not contain the value 0.310.
No, since the confidence interval contains the value 0.310.
Yes, since the confidence interval does not contain the value 0.310.
Yes, since the confidence interval contains the value 0.310.
d. Can we conclude at 99% confidence that the population proportion differs from 0.310? (Multiple choice)
No, since the confidence interval contains the value 0.310.
No, since the confidence interval does not contain the value 0.310.
Yes, since the confidence interval contains the value 0.310.
Yes, since the confidence interval does not contain the value 0.310.
Homework Answers
Answer #1
Given that, a sample of 160 results in 40 successes.
a) The point estimate for the population proportion of successes = 40/160 = 0.250
b) A 95% confidence level has significance level = 0.05 and
critical value is, 
95% confidence interval for p is,
The 95% CI is, (0.1829, 0.3171)
A 99% confidence level has significance level = 0.01 and
critical value is, 
99% confidence interval for p is,
The 99% CI is, (0.1619, 0.3381)
c) No, since the confidence interval contains the value 0.310
d) No, since the confidence interval contains the value 0.310
Not the answer you're looking for?
Similar Questions
A sample of 80 results in 30 successes. [You may find it useful to reference the...
A sample of 80 results in 30 successes. [You may find it
useful to reference the z table.]
a. Calculate the point estimate for the
population proportion of successes. (Do not round
intermediate calculations. Round your answer to 3 decimal
places.)
b. Construct 90% and 99% confidence intervals
for the population proportion. (Round intermediate
calculations to at least 4 decimal places. Round "z" value
and final answers to 3 decimal
places.)
c. Can we conclude at 90% confidence that...
3. A sample of 95 results in 57 successes. Use Table 1. Please do not post...
3. A sample of 95 results in 57 successes. Use
Table 1. Please do not post if you are unsure. THANK YOU!
a. Calculate the point estimate for the population proportion of
successes. (Do not round intermediate calculations.
Round your answer to 3 decimal places.)
POINT ESTIMATE
0.600 (CORRECT)
b. Construct 99% and 90% confidence intervals for the population
proportion. (Round intermediate calculations to 4
decimal places. Round "z-value" and final answers to 3 decimal
places.)
Confidence Level
Confidence...
An economist reports that 1,144 out of a sample of 2,600 middle-income American households actively participate...
An economist reports that 1,144 out of a sample of 2,600
middle-income American households actively participate in the stock
market.
A) Find the lower bound of the 99% confidence interval for the
proportion of middle-income Americans who actively participate in
the stock market. (Round intermediate calculations to 3 decimal
places. Round "z-value" and final answers to 3 decimal places.
B) Find the upper bound of the 99% confidence interval for the
proportion of middle-income Americans who actively participate in
the...
An economist reports that 700 out of a sample of 2,800 middle-income American households actively participate...
An economist reports that 700 out of a sample of 2,800
middle-income American households actively participate in the stock
market.Use Table 1.
a.
Construct the 90% confidence interval for the proportion of
middle-income Americans who actively participate in the stock
market. (Round intermediate calculations to 4 decimal
places. Round "z-value" and final answers to 3 decimal
places.)
Confidence
interval
to
b.
Can we conclude that the proportion of middle-income Americans
who actively participate in the stock market...
A machine that is programmed to package 5.20 pounds of cereal is being tested for its...
A machine that is programmed to package 5.20 pounds of cereal is
being tested for its accuracy. In a sample of 100 cereal boxes, the
sample mean filling weight is calculated as 5.26 pounds. The
population standard deviation is known to be 0.08 pound. [You may
find it useful to reference the z table.]
a-1. Identify the relevant parameter of interest for these
quantitative data. Multiple choice, pick one answer.
-The parameter of interest is the proportion filling weight of...
Consider the following data drawn independently from normally distributed populations: (You may find it useful to...
Consider the following data drawn independently from normally
distributed populations: (You may find it useful to
reference the appropriate table: z table
or t table)
x−1x−1 = 29.8
x−2x−2 = 32.4
σ12 = 95.3
σ22 = 91.6
n1 = 34
n2 = 29
a. Construct the 99% confidence interval for the
difference between the population means.
(Negative values should be indicated by a
minus sign. Round all intermediate calculations to at least 4
decimal places and final answers to 2...
Consider the following data drawn independently from normally distributed populations: (You may find it useful to...
Consider the following data drawn independently from normally
distributed populations: (You may find it useful to
reference the appropriate table: z table
or t table)
x−1x−1 = 28.5
x−2x−2 = 29.8
σ12 = 96.9
σ22 = 87.0
n1 = 29
n2 = 25
a. Construct the 99% confidence interval for the
difference between the population means.
(Negative values should be indicated by a
minus sign. Round all intermediate calculations to at least 4
decimal places and final answers to 2...
A machine that is programmed to package 3.30 pounds of cereal is being tested for its...
A machine that is programmed to package 3.30 pounds of cereal is
being tested for its accuracy. In a sample of 49 cereal boxes, the
sample mean filling weight is calculated as 3.39 pounds. The
population standard deviation is known to be 0.14 pound.
[You may find it useful to reference the z
table.]
a-1. Identify the relevant parameter of
interest for these quantitative data.
The parameter of interest is the proportion filling weight of
all cereal packages.
The parameter...
Consider the following data drawn independently from normally distributed populations: (You may find it useful to...
Consider the following data drawn independently from normally
distributed populations: (You may find it useful to
reference the appropriate table: z table
or t table)
x−1x−1 = 34.4
x−2x−2 = 26.4
σ12 = 89.5
σ22 = 95.8
n1 = 21
n2 = 23
a. Construct the 90% confidence interval for the
difference between the population means.
(Negative values should be indicated by a
minus sign. Round all intermediate calculations to at least 4
decimal places and final answers to 2...
A machine that is programmed to package 5.69 pounds of cereal is being tested for its...
A machine that is programmed to package 5.69 pounds of cereal is
being tested for its accuracy. In a sample of 100 cereal boxes, the
sample mean filling weight is calculated as 5.69 pounds. The
population standard deviation is known to be 0.05 pound. Use Table
1.
a-1.
Identify the relevant parameter of interest for these
quantitative data.
The parameter of interest is the average filling weight of all
cereal packages.
The parameter of interest is the proportion filling...
ADVERTISEMENT
Need Online Homework Help?
Get Answers For Free
Most questions answered within 1 hours.
ADVERTISEMENT
Active Questions
asked 1 minute ago
asked 21 minutes ago
asked 25 minutes ago
asked 28 minutes ago
asked 31 minutes ago
asked 35 minutes ago
asked 44 minutes ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago