A sample of 80 results in 30 successes. [You may find it
useful to reference the z table.]
a. Calculate the point estimate for the population proportion of successes. (Do not round intermediate calculations. Round your answer to 3 decimal places.)
b. Construct 90% and 99% confidence intervals for the population proportion. (Round intermediate calculations to at least 4 decimal places. Round "z" value and final answers to 3 decimal places.)
c. Can we conclude at 90% confidence that the population proportion differs from 0.5?
Yes, since the confidence interval contains the value 0.5.
Yes, since the confidence interval does not contain the value 0.5.
No, since the confidence interval contains the value 0.5.
No, since the confidence interval does not contain the value 0.5.
d. Can we conclude at 99% confidence that the
population proportion differs from 0.5?
Yes, since the confidence interval contains the value 0.5.
Yes, since the confidence interval does not contain the value 0.5.
No, since the confidence interval contains the value 0.5.
No, since the confidence interval does not contain the value 0.5.
c. Can we conclude at 90% confidence that the population proportion differs from 0.5?
d. Can we conclude at 99% confidence that the population proportion differs from 0.5?
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