Question

The 98% confidence interval for the mean, calculated from a sample is 1.275775≤μ≤2.524225. Determine the sample mean =

. Assuming that the data is normally distributed with the population standard deviation =1.2, determine the size of the sample n=

Answer 1

Lower limit = 1.275775

upper limit = 2.524225

mean = (Lower limit + Upper limit) / 2

mean = (1.275775 + 2.524225) / 2

mean = (3.8) / 2

mean = 1.9

Margin of error = upper limit - mean

Margin of error = 2.524225 - 1.9

Margin of error 0.624225

Margin of error (e) = 0.624225
z @ 98.0% = 2.3263
Since we know that

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