Use the given data to find the 95% confidence interval estimate of the population mean μ. Assume that the population has a normal distribution. IQ scores of professional athletes: Sample size n=10 Mean x¯=106 Standard deviation s=12
______<μ<________
solution :
Given that,
= 106
s = 12
n = 10
Degrees of freedom = df = n - 1 = 10 - 1 = 9
a ) At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/
2 = 0.05 / 2 = 0.025
t
/2,df = t0.025,9 =2.262
Margin of error = E = t/2,df
* (s /
n)
= 2.262* (12 /
10) = 8.58
The 95% confidence interval estimate of the population mean is,
- E <
<
+ E
106 - 8.58 <
< 106 + 8.58
97.42<
< 114.58
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