Use the t-distribution to find a confidence interval
for a mean μ given the relevant sample results. Give the best point
estimate for μ, the margin of error, and the confidence interval.
Assume the results come from a random sample from a population that
is approximately normally distributed.
A 95% confidence interval for μ using the sample results x̄ = 79.7,
s = 6.6, and n=42
Round your answer for the point estimate to one decimal place, and
your answers for the margin of error and the confidence interval to
two decimal places.
Point estimate = ______
Margin of error = _______
The 95% Confidence Interval is _______
to _______
Given : = 79.7, s = 6.6, n = 42, = 0.05
Since population standard deviation is unknown, the tcritical (2 tail) for = 0.05, for df = n -1 = 41, is 2.02
The Confidence Interval is given by ME, where
The Lower Limit = 79.7 - 2.06 = 77.64
The Upper Limit = 79.7 + 2.06 = 81.76
The Confidence Interval is 77.64 to 81.76
The Confidence Interval is a < \mu < b
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