Question

The 99% confidence interval for the mean, calculated from a sample is 2.05944 ≤ μ ≤ 3.94056 . Determine the sample mean X ¯ = . Assuming that the data is normally distributed with the population standard deviation =2, determine the size of the sample n =

Answer #1

The 98% confidence interval for the mean, calculated from a
sample is 1.275775≤μ≤2.524225. Determine the sample mean =
. Assuming that the data is normally distributed with the
population standard deviation =1.2, determine the size of the
sample n=

Given a sample size 18 with a 99% confidence interval for the
mean μ, and a known standard deviation (26.64, 33.25), calculate
the 95% confidence interval for μ.

(S 9.2) Recall that a confidence interval for the sample mean
can be calculated using the interval
x¯?tn?1?sn??????x¯+tn?1?sn???
Thus, the margin of error is
tn?1?sn???
We can recover the margin of error from an interval constructed
on the calculator using algebra.
Suppose a random sample of size 16 was taken from a normally
distributed population, and the sample standard deviation was
calculated to be s = 6.3. We'll assume the sample mean is
10 for convenience.
a) Calculate the margin...

Assuming that the population is normally distributed, construct
a
99 %99%
confidence interval for the population mean, based on the
following sample size of n equals 5.n=5.1, 2, 3,
44,
and
2020
In the given data, replace the value
2020
with
55
and recalculate the confidence interval. Using these results,
describe the effect of an outlier (that is, an extreme value) on
the confidence interval, in general.
Find a
99 %99%
confidence interval for the population mean, using the formula...

Assuming that the population is normally distributed, construct
a 99 % confidence interval for the population mean, based on the
following sample size of n equals 5. 1, 2, 3, 4, and 26 In the
given data, replace the value 26 with 5 and recalculate the
confidence interval. Using these results, describe the effect of
an outlier (that is, an extreme value) on the confidence
interval, in general. Find a 99 % confidence interval for the
population mean, using the...

Assume that a sample is used to estimate a population mean μ.
Find the 99% confidence interval for a sample of size 45 with a
mean of 20.1 and a standard deviation of 11.1. Enter your answer as
an open-interval (i.e., parentheses)
accurate to 3 decimal places.
99% C.I. =

Assume that a sample is used to estimate a population mean μ.
Find the 99% confidence interval for a sample of size 46 with a
mean of 47.2 and a standard deviation of 16.3. Enter your answer as
an open-interval (i.e., parentheses)
accurate to 3 decimal places.
99% C.I. =

Assume that a sample is used to estimate a population mean μ.
Find the 99% confidence interval for a sample of size 1107 with a
mean of 32.4 and a standard deviation of 19.7. Enter your answer as
a tri-linear inequality accurate to 3 decimal places.
< μ <

A simple random sample of size n is drawn from a population that
is normally distributed. The sample mean, x ̅, is found to be 108,
and the sample standard deviation, s, is found to be 10. Construct
a 99% confidence interval for μ if the sample size n is 30.

A simple random sample of size n is drawn from a population that
is normally distributed. The sample mean, overbar x, is found to
be 115, and the sample standard deviation, s, is found to be 10.
(a) Construct a 98% confidence interval about μ if the sample
size, n, is 20. (b) Construct a 98% confidence interval about μ
if the sample size, n, is 25. (c) Construct a 99% confidence
interval about μ if the sample size, n,...

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