LSU students can be In-state and out of state. A recent survey shows that 80% students of LSU are In-state.
Let p be the proportion of lsu students who are instate. So we have p= 0.8
Now, n=100, so np=80, np(1-p) = 16
Let X be the number of students of out 100 who are instate, so
P(X>=80) = P(Z>= 80-80/√16) = P(Z>0) = 1- P(Z<0) = 0.5
2. Let q be the proportion of lsu students who are out state. So q=0.2
So nq= 20, nq(1-q) = 16
Let Y be the number of outstate students out of 100,
So P(Y>=80) = P(Z>= 80-20/√16) = P(Z>=15) = 1- P(Z<=15) < 0.000001
So we can say it is 0.
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