One-sixth of the male freshmen entering a large state university school are out-of-state students. If the students are assigned at random to the dormitories, 180 to a building, what is the probability that a given dormitory at least one-fifth of the students are from out of state?
Solution:
given ,
number of sample n = 180
probability of success = 1 / 6 = 0.166
of the students = (1 / 5 ) * 180 = 36
probability that a given dormitory at least one-fifth of the student are from out of state =
=
P(X < 35) = P(X = 1) + ..................+ P(X = 34) = 0.8754
= 1 - 0.8754 = 0.1246
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