Question

Problem 1

Assume a population of field mice in Hardy-Weinberg equilibrium. At birth, we observe the following gene frequencies:

f(A) = 0.6

f(a) = 0.4

The A allele is dominant and produces the natural coat color, while aa produces white. Of 10,000 total animals born, 6,300 natural coat colored and 200 white mice survive to mating.

A) Calculate the selection coefficient s for this population. (Don’t separate the AA and Aa genotypes, work with AA and Aa as one category = natural coat color)

B) What does this value of s mean?

Problem 2.

Assume a population in equilibrium with the following phenotypic frequencies for the polled and horned gene in cattle (hh is the recessive genotype for the horned condition).

Phenotypic frequencies

Polled = 0.64

Horned = 0.36

Calculate the gene and genotypic frequency in the progeny if the parents are mated by negative assortative mating.

Answer 1

i tried my best ,I have only problem 1 solution , if I solve problem 2 ,then I edit the answer, please like the answer