A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes sigma is 2.3 minutes and that the population of times is normally distributed.
10 11 7 12 11 9 6 6 9 7 8 10 6 6 8
construct the 90% and 99% confidence interval for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals.
the 90% confidence interval is(--,--)
the 99% confidence interval is(--,--)
which interval is wider?
The statistic software output for this problem is:
The 90% confidence interval is :(7.42 , 9.34)
The 90% confidence interval is :(6.87 , 9.93)
The 99% confidence interval is wider
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