Question

A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes sigma is 1.9 minutes and that the population of times is normally distributed. 10 10 8 10 10 6 10 11 7 9 7 7 8 12 11 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. The 90% confidence interval is ( nothing, nothing). (Round to one decimal place as needed.)

Answer #1

From the data, we have,

We know that the 90% confidence interval for population mean is given by:

We know that the 990% confidence interval for population mean is given by:

A publisher wants to estimate the mean length of time (in
minutes) all adults spend reading newspapers. To determine this
estimate, the publisher takes a random sample of 15 people and
obtains the results below. From past studies, the publisher
assumes sigma is 2.1 minutes and that the population of times is
normally distributed.
6 10 12 6 6 10 7 7 8 8 11 11 9 10 7
Construct the 90% and 99% confidence intervals for the
population mean....

A publisher wants to estimate the mean length of time (in
minutes) all adults spend reading newspapers. To determine this
estimate, the publisher takes a random sample of 15 people and
obtains the results below. From past studies, the publisher
assumes sigma σ is 2.1 minutes and that the population of times is
normally distributed. 6 9 6 11 6 7 10 12 8 6 8 9 10 10 9
Construct the 90% and 99% confidence intervals for the
population...

A publisher wants to estimate the mean length of time? (in
minutes) all adults spend reading newspapers. To determine this?
estimate, the publisher takes a random sample of 15 people and
obtains the results below. From past? studies, the publisher
assumes standard deviation is 1.7 minutes and that the population
of times is normally distributed.
9
10
6
8
11
7
10
8
7
12
12
11
9
9
9
Construct the? 90% and? 99% confidence intervals for the
population...

A publisher wants to estimate the mean length of time (in
minutes) all adults spend reading newspapers. To determine this
estimate, the publisher takes a random sample of 15 people and
obtains the results below. From past studies, the publisher
assumes sigma is 2.7 minutes and that the population of times is
normally distributed. 12 12 6 9 11 12 9 9 11 10 6 6 12 6 6
Construct the 90% and 99% confidence intervals for the population
mean....

publisher wants to estimate the mean length of time (in
minutes) all adults spend reading newspapers. To determine this
estimate, the publisher takes a random sample of 15 people and
obtains the results below. From past studies, the publisher
assumes sigmaσ is1.9 minutes and that the population of times is
normally distributed.
11
7
8
12
7
11
6
6
9
9
7
8
10
8
10
Construct the 90% and 99% confidence intervals for the
population mean. Which interval...

A publisher wants to estimate the mean length of time (in
minutes) all adults spend reading newspapers. To determine this
estimate, the publisher takes a random sample of 15 people and
obtains the results below. From past studies, the publisher
assumes
sigmaσ
is
2.22.2
minutes and that the population of times is normally
distributed.
99
88
99
1111
66
99
99
77
1212
77
1212
66
99
1212
99
Construct the 90% and 99% confidence intervals for the
population mean....

A research council wants to estimate the mean length of time (in
minutes) that the average U.S. adult spends watching television
using digital video recorders (DVR’s) each day. To determine the
estimate, the research council takes random samples of 35 U.S.
adults and obtains the following times in minutes.
24
27
26
29
33
21
18
24
23
34
17
15
19
23
25
29
36
19
18
22
16
45
32
12
24
35
14
40
30
19
14...

A research council wants to estimate the mean length of time (in
minutes) that the average U.S. adult spends watching television
using digital video recorders (DVR’s) each day. To determine the
estimate, the research council takes random samples of 35 U.S.
adults and obtains the following times in minutes.
24
27
26
29
33
21
18
24
23
34
17
15
19
23
25
29
36
19
18
22
16
45
32
12
24
35
14
40
30
19
14...

A research council wants to estimate the mean length of time (in
minutes) that the average U.S. adult spends watching television
using digital video recorders (DVR’s) each day. To determine the
estimate, the research council takes random samples of 35 U.S.
adults and obtains the following times in minutes.
24
27
26
29
33
21
18
24
23
34
17
15
19
23
25
29
36
19
18
22
16
45
32
12
24
35
14
40
30
19
14...

A random sample of fifty dash eight 200-meter swims has a mean
time of 3.253 minutes. The population standard deviation is 0.060
minutes. A 95% confidence interval for the population mean time is
left parenthesis 3.240 comma 3.266 right parenthesis.
Construct a
9595%
confidence interval for the population mean time using a
population standard deviation of
0.030.03
minutes. Which confidence interval is wider? Explain.
The
9595%
confidence interval is
(nothing,nothing).
(Round to three decimal places as needed.)
Which confidence interval...

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