Question

A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes sigma is 1.9 minutes and that the population of times is normally distributed. 10 10 8 10 10 6 10 11 7 9 7 7 8 12 11 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. The 90% confidence interval is ( nothing, nothing). (Round to one decimal place as needed.)

Answer #1

From the data, we have,

We know that the 90% confidence interval for population mean is given by:

We know that the 990% confidence interval for population mean is given by:

A publisher wants to estimate the mean length of time (in
minutes) all adults spend reading newspapers. To determine this
estimate, the publisher takes a random sample of 15 people and
obtains the results below. From past studies, the publisher
assumes sigma is 2.1 minutes and that the population of times is
normally distributed.
6 10 12 6 6 10 7 7 8 8 11 11 9 10 7
Construct the 90% and 99% confidence intervals for the
population mean....

A publisher wants to estimate the mean length of time (in
minutes) all adults spend reading newspapers. To determine this
estimate, the publisher takes a random sample of 15 people and
obtains the results below. From past studies, the publisher
assumes sigma σ is 2.1 minutes and that the population of times is
normally distributed. 6 9 6 11 6 7 10 12 8 6 8 9 10 10 9
Construct the 90% and 99% confidence intervals for the
population...

A publisher wants to estimate the mean length of time? (in
minutes) all adults spend reading newspapers. To determine this?
estimate, the publisher takes a random sample of 15 people and
obtains the results below. From past? studies, the publisher
assumes standard deviation is 1.7 minutes and that the population
of times is normally distributed.
9
10
6
8
11
7
10
8
7
12
12
11
9
9
9
Construct the? 90% and? 99% confidence intervals for the
population...

A publisher wants to estimate the mean length of time (in
minutes) all adults spend reading newspapers. To determine this
estimate, the publisher takes a random sample of 15 people and
obtains the results below. From past studies, the publisher
assumes sigma is 2.7 minutes and that the population of times is
normally distributed. 12 12 6 9 11 12 9 9 11 10 6 6 12 6 6
Construct the 90% and 99% confidence intervals for the population
mean....

publisher wants to estimate the mean length of time (in
minutes) all adults spend reading newspapers. To determine this
estimate, the publisher takes a random sample of 15 people and
obtains the results below. From past studies, the publisher
assumes sigmaσ is1.9 minutes and that the population of times is
normally distributed.
11
7
8
12
7
11
6
6
9
9
7
8
10
8
10
Construct the 90% and 99% confidence intervals for the
population mean. Which interval...

A publisher wants to estimate the mean length of time (in
minutes) all adults spend reading newspapers. To determine this
estimate, the publisher takes a random sample of 15 people and
obtains the results below. From past studies, the publisher
assumes
sigmaσ
is
2.22.2
minutes and that the population of times is normally
distributed.
99
88
99
1111
66
99
99
77
1212
77
1212
66
99
1212
99
Construct the 90% and 99% confidence intervals for the
population mean....

A research council wants to estimate the mean length of time (in
minutes) that the average U.S. adult spends watching television
using digital video recorders (DVR’s) each day. To determine the
estimate, the research council takes random samples of 35 U.S.
adults and obtains the following times in minutes.
24
27
26
29
33
21
18
24
23
34
17
15
19
23
25
29
36
19
18
22
16
45
32
12
24
35
14
40
30
19
14...

You are given the sample mean and the population standard
deviation. Use this information to construct the 90% and 95%
confidence intervals for the population mean. Interpret the results
and compare the widths of the confidence intervals. If convenient,
use technology to construct the confidence intervals. A random
sample of 45 45 home theater systems has a mean price of $ 137.00
137.00. Assume the population standard deviation is $ 16.60 16.60.
Construct a 90% confidence interval for the population...

You are given the sample mean and the sample standard deviation.
Use this information to construct the 90% and 95% confidence
intervals for the population mean. Which interval is wider? If
convenient, use technology to construct the confidence
intervals.
A random sample of
3131
gas grills has a mean price of
$625.50625.50
and a standard deviation of
$59.3059.30.
The 90% confidence interval is
left parenthesis nothing comma nothing right parenthesis
.607.981,643.019.
(Round to one decimal place as needed.)The 95% confidence...

You are given the sample mean and the sample standard deviation.
Use this information to construct the? 90% and? 95% confidence
intervals for the population mean. Which interval is? wider? If?
convenient, use technology to construct the confidence intervals. A
random sample of 39 gas grills has a mean price of ?$643.60 and a
standard deviation of ?$56.60 The? 90% confidence interval is __ ,
___

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 2 minutes ago

asked 10 minutes ago

asked 10 minutes ago

asked 12 minutes ago

asked 20 minutes ago

asked 21 minutes ago

asked 46 minutes ago

asked 50 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago