publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes sigmaσ is1.9 minutes and that the population of times is normally distributed.
11 |
7 |
8 |
12 |
7 |
11 |
6 |
6 |
9 |
9 |
7 |
8 |
10 |
8 |
10 |
Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals.
1.The 90% confidence interval is
(Round to one decimal place as needed.)
2.The 99% confidence interval is
(Round to one decimal place as needed.)
3. Which interval is wider?
The 99% confidence interval
The 90% confidence interval
The statistical software output for this problem is :
1.The 90% confidence interval is
(7.7 , 9.5)
2.The 99% confidence interval is
(7.2 , 10.0)
3)
The 99% confidence interval
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