Question

A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes

sigmaσ

is

2.22.2

minutes and that the population of times is normally distributed.

99 |
88 |
99 |
1111 |
66 |
99 |
99 |
77 |
1212 |
77 |
1212 |
66 |
99 |
1212 |
99 |

Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals.

The 90% confidence interval is

(8.18.1,9.99.9).

(Round to one decimal place as needed.)The 99% confidence interval is

(7.57.5,10.510.5).

(Round to one decimal place as needed.)

Which interval is wider?

The 90% confidence interval

The 99% confidence interval

Answer #1

**Solution:- The 99% confidence interval is wider than
90% confidence interval.**

**90% confidence intervals for the population mean is C.I
= (8.1, 9.9)**

C.I = 9 + 1.645 × 0.56804

C.I = 9 + 0.934

**C.I = (8.1, 9.9)**

**99% confidence intervals for the population mean is C.I
= (7.5, 10.5).**

C.I = 9 + 2.576 × 0.56804

C.I = 9 + 1.46427

**C.I = (7.5, 10.5)**

**The 99% confidence interval is wider than 90%
confidence interval.**

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11
7
8
12
7
11
6
6
9
9
7
8
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8
10
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A publisher wants to estimate the mean length of time (in
minutes) all adults spend reading newspapers. To determine this
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9
10
6
8
11
7
10
8
7
12
12
11
9
9
9
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minutes) all adults spend reading newspapers. To determine this
estimate, the publisher takes a random sample of 15 people and
obtains the results below. From past studies, the publisher
assumes sigma is 2.7 minutes and that the population of times is
normally distributed. 12 12 6 9 11 12 9 9 11 10 6 6 12 6 6
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minutes) all adults spend reading newspapers. To determine this
estimate, the publisher takes a random sample of 15 people and
obtains the results below. From past studies, the publisher
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adults and obtains the following times in minutes.
24
27
26
29
33
21
18
24
23
34
17
15
19
23
25
29
36
19
18
22
16
45
32
12
24
35
14
40
30
19
14...

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minutes) that the average U.S. adult spends watching television
using digital video recorders (DVR’s) each day. To determine the
estimate, the research council takes random samples of 35 U.S.
adults and obtains the following times in minutes.
24
27
26
29
33
21
18
24
23
34
17
15
19
23
25
29
36
19
18
22
16
45
32
12
24
35
14
40
30
19
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left parenthesis nothing comma nothing right parenthesis
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