Ten people each have a deck of 52 playing cards. Each person randomly selects 15 cards from their deck without replacement. What is the probability that exactly three of the ten people select exactly five clubs?
(A) 0.1449 (B) 0.1508 (C) 0.1653 (D) 0.1781 (E) 0.1826
Solution: Option( D ) = 0.1781
total number of cards = 52
number of cards to be selected by a person = 15
number of clubs in a pack = 13
total number of ways of selecting 15 cards = 52C13 = 52! / 13!(52-13)! = 4481381406320
number of ways of selecting exactly 5 clubs = 13C5 * 39C10 = 1287 * 635745396 = 818204324652
probability of ways of selecting exactly 5 clubs = 818204324652 / 4481381406320 = 0.1825
now,
number of people to be selected = n = 10
probability of a random person selecting exactly 5 clubs = p = 0.1825
binomial probability distribution
Formula:
P(k out of n )= n!*pk * qn-k / k! *(n - k)!
P( x = 3 ) = 10!*0.18253 * 0.817510-3 / 3! *(10 - 3)!
= 0.1781
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