Question

A. For the following distribution, X P(x) 0 0.130    1 0.310    2 0.350   ...

A.

For the following distribution,

X P(x)
0 0.130   
1 0.310   
2 0.350   
3 0.190   
4 0.020   

What is the mean of the distribution?

A. 0.890

B. 1.660

C. 0.480

D. 1.042

B.

For a binomial distribution, the mean is 0.6 and n = 2. What is π for this distribution?

A. 2.6

B. 0.3

C. 5.0

D. 1.3

C.

For a binomial distribution, the mean is 5.0 and n = 5. What is π for this distribution?

A. 0.5

B. 1.0

C. 0.8

D.2.0

D.

For a standard normal distribution, what is the probability that z is greater than 1.75?

A. 0.0684

B. 0.0401

C. 0.0456

D. 0.0912

E.

The mean of a normally distributed group of weekly incomes of a large group of executives is $1,262 and the standard deviation is $108. What is the z-score for an income of $1,533?

A. 2.51

B. 0.50

C. 2.00

D. 10.00

Homework Answers

Answer #1

a) From the given data

X P(X=x) xP(X=x)
0 0.13 0
1 0.31 0.31
2 0.35 0.7
3 0.19 0.57
4 0.02 0.08
Total: 1 1.66

Mean = 1.66

Correct Answer: Option (B) 1.66

2. Given mean = 0.6 and n =2
In binomial distribution mean = np
0.6 = np
0.6 = 2*p
p = 0.6/2 = 0.3


Correct Answer: Option (B) 0.3

3. Given mean = 5 and n = 5
In binomial distribution mean = np
5 = np
5 = 5*p
p = 5/5 = 1

Correct Answer: Option (B) 1

4.  Correct Answer: Option (B) 0.0401

The probability that z is greater than 1.75 is 0.0401

5. Z-Score = ($1,533 - $1,262) / $108 = 2.51

Correct Answer: Option (A) 2.51

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