A.
For the following distribution,
X | P(x) |
0 | 0.130 |
1 | 0.310 |
2 | 0.350 |
3 | 0.190 |
4 | 0.020 |
What is the mean of the distribution?
A. 0.890
B. 1.660
C. 0.480
D. 1.042
B.
For a binomial distribution, the mean is 0.6 and n = 2. What is π for this distribution?
A. 2.6
B. 0.3
C. 5.0
D. 1.3
C.
For a binomial distribution, the mean is 5.0 and n = 5. What is π for this distribution?
A. 0.5
B. 1.0
C. 0.8
D.2.0
D.
For a standard normal distribution, what is the probability that z is greater than 1.75?
A. 0.0684
B. 0.0401
C. 0.0456
D. 0.0912
E.
The mean of a normally distributed group of weekly incomes of a large group of executives is $1,262 and the standard deviation is $108. What is the z-score for an income of $1,533?
A. 2.51
B. 0.50
C. 2.00
D. 10.00
a) From the given data
X | P(X=x) | xP(X=x) |
0 | 0.13 | 0 |
1 | 0.31 | 0.31 |
2 | 0.35 | 0.7 |
3 | 0.19 | 0.57 |
4 | 0.02 | 0.08 |
Total: | 1 | 1.66 |
Mean = 1.66
Correct Answer: Option (B) 1.66
2. Given mean = 0.6 and n =2
In binomial distribution mean = np
0.6 = np
0.6 = 2*p
p = 0.6/2 = 0.3
Correct Answer: Option (B) 0.3
3. Given mean = 5 and n = 5
In binomial distribution mean = np
5 = np
5 = 5*p
p = 5/5 = 1
Correct Answer: Option (B) 1
4. Correct Answer: Option (B) 0.0401
The probability that z is greater than 1.75 is 0.0401
5. Z-Score = ($1,533 - $1,262) / $108 = 2.51
Correct Answer: Option (A) 2.51
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