Question
6. You have been provided the following probability distribution: Pets P(x) x*P(x) (x-µ)²P(x) 0 0.330 1...
| 6. You have been provided the following probability distribution: | |||
| Pets | P(x) | x*P(x) | (x-µ)²P(x) |
| 0 | 0.330 | ||
| 1 | 0.270 | ||
| 2 | 0.300 | ||
| 3 | 0.050 | ||
| 4 | 0.025 | ||
| 5 | 0.020 | ||
| 6 or more | 0.005 | ||
| Let x = the total number of pets in a household | |||
| a. Complete table | |||
| b. What is the probability of a household having no pets? | |||
| c. What is the probability of a household having exactly 3 pets? | |||
| d. What is the probability of a household having between 1 and 3 pets? | |||
| e. What is the probability of a household having more than 5 pets? | |||
| f. On average, how many pets does a household have? | |||
| g. Calculate the standard deviation. | |||
| h. What is 1 standard deviations below the mean? | |||
| i. What is 1.5 standard deviations above the mean? | |||
| j. What is 3 standard deviations above the mean? | |||
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