Question

Consider the following probability distribution table: X 1 2 3 4 P(X) .1 .2 .3 .4...

Consider the following probability distribution table:

X

1

2

3

4

P(X)

.1

.2

.3

.4

If Y = 2+3X, E(Y) is:

A.7 B.8 C.11 D.2

19.

If Y=2+3X, Var (Y) is:

A.9

B.14

C.4

D.6

20.

Which of the following about the binomial distribution is not a true statement?

A. The probability of success is constant from trial to trial. B. Each outcome is independent of the other. C. Each outcome is classified as either success or failure. D. The random variable of interest is continuous.

Homework Answers

Answer #1

Solution :

Mean = = X * P(X)

= 1 * 0.1 + 2 * 0.2 + 3 * 0.3 + 4 * 0.4

= 0.1 + 0.4 + 0.9 + 1.6

E(X) = = 3

If Y = 2 + 3 X,

E(Y) = 2 + 3 E(X) = 2 + 3 * 3 = 2 + 9 = 11

E(Y) = 11

Option C)

variance

= X 2 * P(X) - 2

=   12 * 0.1 + 22 * 0.2 + 32 * 0.3 + 42 * 0.4 - 32

= 0.1 + 0.8 + 2.7 + 6.4 - 9

Var(X) = 1

If Y = 2 + 3 X,

Var (Y) = 9 Var(X) = 9 * 1 = 9

Var (Y) = 9

Option A)

Not a true statement about the binomial distribution is ,

D. The random variable of interest is continuous.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
(1) Consider X that follows the Bernoulli distribution with success probability 1/4, that is, P(X =...
(1) Consider X that follows the Bernoulli distribution with success probability 1/4, that is, P(X = 1) = 1/4 and P(X = 0) = 3/4. Find the probability mass function of Y , when Y = X4 . Find the second moment of Y . (2) If X ∼ binomial(10, 1/2), then use the binomial probability table (Table A.1 in the textbook) to find out the following probabilities: P(X = 5), P(2.9 ≤ X ≤ 4.9) (3) A deck of...
True or False: 10. The probability of an event is a value which must be greater...
True or False: 10. The probability of an event is a value which must be greater than 0 and less than 1. 11. If events A and B are mutually exclusive, then P(A|B) is always equal to zero. 12. Mutually exclusive events cannot be independent. 13. A classical probability measure is a probability assessment that is based on relative frequency. 14. The probability of an event is the product of the probabilities of the sample space outcomes that correspond to...
1. For a discrete distribution the pmf = x/10   for x = 1, 2, 3, 4....
1. For a discrete distribution the pmf = x/10   for x = 1, 2, 3, 4. What is the expected value for this distribution? Give your answer to four decimal places. 2. The pmf for a discrete distribution is given by p(x) = 1/3 for x = -1, 0, 1. What is the variance of this distribution? Give your answer to four decimal places. 3. You have invented a new procedure for which the outcome can be classified as either...
In an experiment, there are n independent trials. For each trial, there are three outcomes, A,...
In an experiment, there are n independent trials. For each trial, there are three outcomes, A, B, and C. For each trial, the probability of outcome A is 0.20; the probability of outcome B is 0.30; and the probability of outcome C is 0.50. Suppose there are 10 trials. (a) Can we use the binomial experiment model to determine the probability of four outcomes of type A, five of type B, and one of type C? Explain. No. A binomial...
In an experiment, there are n independent trials. For each trial, there are three outcomes, A,...
In an experiment, there are n independent trials. For each trial, there are three outcomes, A, B, and C. For each trial, the probability of outcome A is 0.10; the probability of outcome B is 0.60; and the probability of outcome C is 0.30. Suppose there are 10 trials. (a) Can we use the binomial experiment model to determine the probability of four outcomes of type A, five of type B, and one of type C? Explain. No. A binomial...
Which of the following is a condition for the binomial distribution? A. The probability of success...
Which of the following is a condition for the binomial distribution? A. The probability of success p is the same for all possible observations. B. Each observation may have only two possible outcomes: success or failure. C. There are a fixed number of independent observations, n. D. All of these choices are correct.
Consider the following joint distribution between random variables X and Y: Y=0 Y=1 Y=2 X=0 P(X=0,...
Consider the following joint distribution between random variables X and Y: Y=0 Y=1 Y=2 X=0 P(X=0, Y=0) = 5/20 P(X=0, Y=1) =3/20 P(X=0, Y=2) = 1/20 X=1 P(X=1, Y=0) = 3/20 P(X=1, Y=1) = 4/20 P(X=1, Y=2) = 4/20 Further, E[X] = 0.55, E[Y] = 0.85, Var[X] = 0.2475 and Var[Y] = 0.6275. a. (6 points) Find the covariance between X and Y. b. (6 points) Find E[X | Y = 0]. c. (6 points) Are X and Y independent?...
The main difference between hypergeometric and binomial distributions is that, with the hypergeometric distribution, the _____....
The main difference between hypergeometric and binomial distributions is that, with the hypergeometric distribution, the _____. Select one: a. trials are independent of each other b. probability of success must be less than .5 c. probability of success changes from trial to trial d. random variable is continuous
Consider the following cumulative probability distribution. x 0 1 2 3 4 5 P(X ≤ x)...
Consider the following cumulative probability distribution. x 0 1 2 3 4 5 P(X ≤ x) 0.10 0.29 0.48 0.68 0.84 1 a. Calculate P(X ≤ 2). (Round your answer to 2 decimal places.) b. Calculate P(X = 2). (Round your answer to 2 decimal places.) c. Calculate P(2 ≤ X ≤ 4). (Round your answer to 2 decimal places.)
Suppose the joint probability distribution of X and Y is given by the following table. Y=>3...
Suppose the joint probability distribution of X and Y is given by the following table. Y=>3 6 9 X 1 0.2 0.2 0 2 0.2 0 0.2 3 0 0.1 0.1 The table entries represent the probabilities. Hence the outcome [X=1,Y=6] has probability 0.2. a) Compute E(X), E(X2), E(Y), and E(XY). (For all answers show your work.) b) Compute E[Y | X = 1], E[Y | X = 2], and E[Y | X = 3]. c) In this case, E[Y...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT